MCQ on Mass Defect
Q1: If the radius of the 13Al27 nucleus is taken to be RAl then the radius of 53Te125 nucleus is nearly
- 5/3 RAl
- ⅗ RAl
- (13/53) ⅓ RAl
Answer: (b) 5/3 RAl
Q2: A nucleus of uranium decays at rest into nuclei of thorium and helium. Then,
- The helium nucleus has more kinetic energy than the thorium nucleus
- The helium nucleus has less momentum than the thorium nucleus
- The helium nucleus has more momentum than the thorium nucleus
- The helium nucleus has less kinetic energy than the thorium nucleus
Answer: (a) The helium nucleus has more kinetic energy than the thorium nucleus
Q3: The binding energy per nucleon of 3Li7 and 2He4 nuclei are 5.60 meV and 7.06meV respectively.
In the nuclear reaction 3Li7 + 1H1 ➡️ 2He4 +2He4+Q, the value of energy Q released is
- 19.6 MeV
- -2.4 MeV
- 8.4 MeV
- 17.3 MeV
Answer: (d) 17.3 MeV
Q4: Calculate the mass defect(amu/atom) for a 37Cl atom for which the actual mass is 36.966 amu.
- 0.341 amu
- 0.388 amu
- 0.623 amu
- 0.264 amu
Answer: (a) 0.341 amu
Q5: The mass defect for an isotope is 0.410 amu/atom. Calculate the value of binding energy.
- 1.23 x 1020 kJ/mol
- 2.23 x 103 kJ/mol
- 3.69 x 1010 kJ/mol
- 3.69 x 1013 kJ/mol
Answer: (c) 3.69 x 1010 kJ/mol
Q6: Which isotope below has the highest binding energy?
Answer: (d) 55Mn
Q7: Which of the following sentences is incorrect?
- Nuclear binding energy is the energy released in the formation of an atom from subatomic particles
- It the nucleus was formed from initially separated protons and electrons then the amount of matter converted into energy was called Mass defect.
- The total mass of protons and electrons in the atom.
- The most stable nuclei are molecules with the highest binding energy.
Answer: (c) The total mass of protons and electrons in the atom
Q8: A nucleus has a mass number A, atomic number Z and a binding energy B. The mass of neutron and proton are mn and mp respectively and cis the speed of light.
Which of the following expressions correctly represents the mass of the nucleus?
- (A – Z)mn+Zmp-B/c2
- (A – Z)mn+Zmp+ B/c2
- (A + Z)mn+Zmp– B/c2
- (A + Z)mn+Zmp+ B/c2
Answer: (a) (A – Z)mn+Zmp-B/c2